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To
Bounce or Not to Bounce
Projectile Range Activity
Graphing Calculator Activity
Advanced Activity
Calculator skills graphing
parametric equations
Directions are based on the use of a TI83 graphing
calculator.
| Starting points: |
- Speed of a hard line drive = 110 mph
- 110 mph (1 m/s / 2.24 mph) = 49.1
m/s
- Angle of line drive above the field as
it leaves the bat = 15o
- Initial height of ball off the field as
it leaves the bat = 3.28 ft = 1.0 m
- Distance to the outfield wall = 350 ft
- 350 ft (1 m/3.28 ft) = 106.7 m
- Height of the outfield fence = 10 ft
- 10 ft (1 m/3.28 ft) = 3.05 m
- Acceleration due to gravity, straight down
= -9.8 m/s2
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In most graphs, the x axis (the domain) determines
the value of the y axis (the range) through a function
of some kind. Or we can say, x tells y what to be.
For example, if y = 2x, then whatever x is, y is twice
that much. If instead y = x +5, then whatever x is,
y is that plus 5.
In this lesson you'll make a different kind of graph,
where a third, hidden variable tells both x
and y what to be. (Think of a puppeteer above the
stage controlling both the arms and legs of a puppet.
Or think of the wizard in The Wizard of Oz,
running things from behind a curtain.) There's nothing
sinister about these graphs, though -- time (t) is
the variable that will be controlling x (the distance
the ball moves across the field) and y (its
distance above the field). When two equations
depend on a third variable for their values, they
are called parametric equations.
Let's start from the simple case where we ignore
air friction and the spin of the ball. After the ball
leaves the bat it has two separate motions: out across
the field (the x direction) and up and down above
the field (the y direction). We call those separate
motions the components of the ball's motion.
Our first step is to break down the ball's initial
velocity (vo) into its two components,
vx and vy. Their magnitudes
or sizes are given by
vx = vo cos 2
vy = vo sin 2
where 2 is the angle above the field at which the
ball leaps off the bat.
The key idea is that gravity always pulls straight
down, so the y component is accelerated motion but
the x component is constant, steady, uniform motion.
The distance away from the plate (x) and the distance
above the field (y) are found by
x = vo cos 2 t
y = vo sin 2 t + _ at2
OK! So how do you make your calculator do that? First,
be sure it's set to degrees, parametric mode and sequential
graphing. Click the mode button next to the 2nd key.
Next, let's draw the outfield fence. Since the fence
doesn't move, for all values of t it's 106.7 m away
in our example. So enter 106.7 for equation X1T.
To make a vertical line for the fence, enter the height
of the fence, 3.05 m, minus time.
Press [WINDOW] to set the graph viewing rectangle.
Set Tmin, xmin, and ymin
to zero. Tmax is the total time the ball
is in the air. Try about 3 seconds. Tstep
determines the plotting speed and resolution of the
calculator. The smaller the number, the more precise
your results, but the longer it will take to plot.
The calculator runs faster with a larger number but
the graph will fail to represent the actual path of
the ball. A good time step for this example is about
0.05 second, so set Tstep = .05. xmax
is the total length of the field. Make it a
little bigger than the distance to the fence, or about
110 m. Finally, ymax is the distance above
the field that we wish to view. Let's try 50 m for
this example.
Press [GRAPH] and see if you have a little home run
fence in the far corner of the screen.
Now let's draw the hit and see how it goes! Enter
these equations as the second set in your equation
editor:
X2T = 49.1 cos (15)T
Y2T = 49.1 sin (15)T - 4.9T2
+ 1
Look back to the original numbers for this example.
Do you see where they fit in these equations?
Press [GRAPH], make a sound like the crack of a bat
if you want to add some realism and watch the ball
fly! It's outta there!!
Just how good a homer was that? Press [TRACE] and
cursor down to choose equation set 2. Then cursor
right to follow the ball's path. When x is close to
the distance of the outfield fence (106.7 m), check
the value of y and see how much bigger it is than
the height of the fence, 3.05 m. You can also check
the value of T to see how long the ball was in the
air before it left the park.
Going Further
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Try other values of initial speed and angle;
just be sure to change the values in both the
x and y equations. It's amazing how little you
have to change either variable to make a homer
into a catchable ball, or vice versa. Baseball
is a game of inches!
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Add the drag force, the retarding force caused
by air resistance. At line drive speeds, drag
approximately equals the weight of the ball, a
force large enough to radically change the ball's
motion. It's convenient for us that the forces
are about equal; all we should have to do is add
a -4.9T2 term to the x equation. The
trouble is, that would assume that the drag force
is always horizontal, but it's not; it's always
pointing opposite the motion of the ball. It would
be way beyond the scope of these lessons to write
equations that reflect the way air drag slows
the ball in both the horizontal and vertical directions.
You can get an approximate solution by changing
your equations to look like these:
X2T = 49.1 cos (15)T - 2.6T2
Y2T = 49.1 sin (15)T - 7.5T2
+1
Changes are based on curves of ball trajectories
in The Physics of Baseball by Robert Adair.
The x equation is fairly accurate, as air drag increasingly
reduces the ball's horizontal velocity the longer
the ball flies. The y equation is fairly accurate
while the ball is rising because the air drag effectively
reduces the ball's vertical velocity as if gravitation
were stronger. However, after the ball reaches its
peak, air drag tends to oppose gravity and should
reduce the value of -7.5 to something smaller than
-4.9.
Press [GRAPH] to run the play again. What a difference!
The ball that was an easy home run, without air
friction, is now just a routine fly ball. How far
does it travel? When does it hit the ground, if
no one happens to catch it? Use [TRACE] to find
those answers.
Remember that the width of the window is 110 m,
but the height is 50 m, so the graph is not exactly
to scale. More importantly, remember that air drag
is quite complicated and is impossible to represent
accurately here.
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